# Problem #1140

 1140 A rectangle with diagonal length $x$ is twice as long as it is wide. What is the area of the rectangle? $(\mathrm {A}) \ \frac 14x^2 \qquad (\mathrm {B}) \ \frac 25x^2 \qquad (\mathrm {C})\ \frac 12x^2 \qquad (\mathrm {D}) \ x^2 \qquad (\mathrm {E})\ \frac 32x^2$ This problem is copyrighted by the American Mathematics Competitions.
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