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A sphere is inscribed in a truncated right circular cone as shown. The volume of the truncated cone is twice that of the sphere. What is the ratio of the radius of the bottom base of the truncated cone to the radius of the top base of the truncated cone?
This problem is copyrighted by the American Mathematics Competitions.
Instructions for entering answers:
- Reduce fractions to
lowest terms and enter in the form 7/9.
- Numbers involving pi should be written as 7pi or 7pi/3
- Square roots should be written as sqrt(3),
5sqrt(5), sqrt(3)/2, or 7sqrt(2)/3 as appropriate.
- Exponents should be entered in the form 10^10.
- If the problem is multiple choice, enter the appropriate
- Enter points with parentheses, like so: (4,5)
- Complex numbers should be entered in rectangular form
unless otherwise specified, like so: 3+4i. If there is no
real component, enter only the imaginary component (i.e. 2i,
For questions or comments, please email firstname.lastname@example.org.